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本文介紹了如何將一個數組輸入與另一個數組輸入相關聯？的處理方法，對大家解決問題具有一定的參考價值，需要的朋友們下面隨著小編來一起學習吧！

問題描述

假設我有2個掃描儀填充的數組，name[]和age[]。每一張都是按順序填寫的。如果我要查找數組中年齡最大的人，我如何使用數組打印出他們的姓名和年齡？
例如，age[]中最大的條目是78。有沒有辦法將其與name[]數組關聯以將其打印出來？

參考編碼：

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    System.out.println("How many entries ?");

    int entries;
    do {
        entries = input.nextInt();
        if (entries < 1) {
            System.out.println("please enter a valid number!");
        }
    } while (entries < 1);

    String[] name = new String[entries];
    String[] gender = new String[entries];
    int[] age = new int[entries];

    for (int i = 0; i < entries; i++) {
        System.out.println("Enter the name of person No" + (i + 1) + ".");
        name[i] = input.next();
    }

    double ageSum = 0;
    int max = 0;
    for (int i = 0; i < entries; i++) {
        System.out.println("How old is " + name[i] + " ?");
        age[i] = input.nextInt();
        ageSum += age[i];
        max = Math.max(max, age[i]);
    }

    System.out.println("the oldest person is "
            + name[] + " whose " + max + " years old.");
}

推薦答案

假設您的數組具有相同的大小和與名稱對應的期限，那么您可以檢查最高期限并存儲具有最高期限的元素的索引。

那么您的名字就在這個指示符上。

int highestAgeIndice = 3; //indice of element with age 97 as example

names[highestAgeIndice] // the corresponding name

計算最高年齡并存儲其索引

int max = 0;
int highestInd = 0;
for (int i = 0; i < age.length; i++) {
    if (age[i] > max) {
        max = age[i];
        highestInd = i;
    }
}

System.out.println("the oldest person is " +
        name[highestInd] + " whose " + max + " years old.");

代碼

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    System.out.println("How many entries ?");

    int entries;
    do {
        entries = input.nextInt();
        if (entries < 1) {
            System.out.println("please enter a valid number!");
        }
    } while (entries < 1);

    String[] name = new String[entries];
    String[] gender = new String[entries];
    int[] age = new int[entries];

    for (int i = 0; i < entries; i++) {
        System.out.println("Enter the name of person No" + (i + 1) + ".");
        name[i] = input.next();
    }

    double ageSum = 0;
    for (int i = 0; i < entries; i++) {
        System.out.println("How old is " + name[i] + " ?");
        age[i] = input.nextInt();
        ageSum += age[i];
    }

    int max = 0;
    int highestInd = 0;
    for (int i = 0; i < age.length; i++) {
        if (age[i] > max) {
            max = age[i];
            highestInd = i;
        }
    }
    System.out.println("the oldest person is " +
            name[highestInd] + " whose " + max + " years old.");
}

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