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本文介紹了使用Java打印鉆石形狀的處理方法，對大家解決問題具有一定的參考價值，需要的朋友們下面隨著小編來一起學習吧！

問題描述

我要在Eclipse的輸出控制臺上打印一個網格形狀。

基本上，我從User中獲取了一個整數，即網格單個邊框中的星星數。

以下是我到目前為止的代碼：

public class PrintDiamond {
    public static void main(String[] args) {
        System.out.print("Enter the number: ");
        Scanner scan = new Scanner(System.in);
        int num = scan.nextInt();
        num--;
        for (int i = num; i > 0; --i) {
            //Insert spaces in order to center the diamond
            for (int n = 0; n < i; ++n) {
                System.out.print("  ");
            }
            System.out.print(" *");
            for (int n = i; n < num; ++n) {
                System.out.print(" + ");
                System.out.print(" ");
            }//Ending bracket of nested for-loop
            System.out.println();
        }//Ending bracket of for loop
        //Print out a diamond shape based on user input
        for (int i = 0; i <= num; ++i) {//<= to print the last asterisk
            //Insert spaces in order to center the diamond
            for (int n = 0; n < i; ++n) {
                System.out.print("  ");
            }
            System.out.print(" *");
            for (int n = i; n < num; ++n) {
                System.out.print(" + ");
                System.out.print(" ");
            }//Ending bracket of nested for-loop
            System.out.println();
        }//Ending bracket of for loop
    }
}

，輸出為(對于int。6)：

           *
         * +  
       * +   +  
     * +   +   +  
   * +   +   +   +  
 * +   +   +   +   +  
   * +   +   +   +  
     * +   +   +  
       * +   +  
         * +  
           *

推薦答案

代碼如下：

public static void main(String[] args) {
    System.out.print("Enter the number: ");
    Scanner scan = new Scanner(System.in);
    int num = scan.nextInt();
    final char[][] diamond = makeDiamond(num);
    for (int i = 0; i < diamond.length; i++) {
        for (int j = 0; j < diamond[i].length; j++) {
            System.out.print(diamond[i][j]);
        }
        System.out.println();
    }
}

public static char[][] makeDiamond(int n) {
    int width = 1 + 4 * (n - 1);
    int height = 1 + 2 * (n - 1);
    char[][] out = new char[height][width];
    int x0 = 2 * (n - 1);
    int y0 = n - 1;
    for (int i = 0; i < width; i += 2) {
        // Top borders
        int y1 = Math.abs(y0 - i / 2);
        out[y1][i] = '*';

        // Bottom borders
        int y2 = height - Math.abs(i / 2 - y0) - 1;
        out[y2][i] = '*';

        if ((x0 - i) % 4 == 0) {
            // Plus signs
            for (int j = y1 + 1; j < y2; j++) {
                out[j][i] = '+';
            }
        }
    }
    return out;
}

這篇關于使用Java打印鉆石形狀的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，