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本文介紹了如何遍歷列表以檢查某項(xiàng)是否為另一個(gè)列表的成員的處理方法，對(duì)大家解決問(wèn)題具有一定的參考價(jià)值，需要的朋友們下面隨著小編來(lái)一起學(xué)習(xí)吧！

問(wèn)題描述

我想檢查診斷代碼列表中的任何項(xiàng)目是否存在于另一個(gè)列表中。

我是Drools的新手，我仍在嘗試確定最佳方法，因?yàn)楫?dāng)前的方法不起作用(輸出顯示為NULL，而它應(yīng)該返回‘true’)。

Java POJO

public class EligibilityDomainObject {
    
    private List<String> listOfString;  
    public List<String> getListOfString() {  
         return listOfString;  
    }  
    public void setListOfString(List<String> listOfString) {  
         this.listOfString = listOfString;  
    }  
    public void addString(String value) {  
         if (listOfString == null) {  
              listOfString = new ArrayList<String>();  
         }  
         listOfString.add(value);  
    }  
    private Boolean isComplexPhysicalHealth;
    public Boolean getIsComplexPhysicalHealth() {
        return this.isComplexPhysicalHealth;
    }

    public void setIsComplexPhysicalHealth(Boolean isComplexPhysicalHealth) {
        this.isComplexPhysicalHealth = isComplexPhysicalHealth;
    }

口水

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject($listOfString : listOfString,
            $listOfString memberOf "F77 EOO F99" )
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
end

Main

    public static void main(String[] args) {
        SpringApplication.run(RulesEngineApplication.class, args);
        

        try {
            KieServices kieServices = KieServices.Factory.get();
            KieContainer kContainer = kieServices.getKieClasspathContainer();

            KieSession kSession = kContainer.newKieSession("ksession-rules");
            
            EligibilityDomainObject eligibilityDomainObject = new EligibilityDomainObject(null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null, null);

            eligibilityDomainObject.addString("F77");
            eligibilityDomainObject.addString("F99");
            System.out.println("List of diagnosis codes: "+ eligibilityDomainObject.getListOfString().toString());
            kSession.insert(eligibilityDomainObject);
            kSession.fireAllRules();
            System.out.println("complex phys health flag: "+ eligibilityDomainObject.getIsComplexPhysicalHealth());
            
            kSession.dispose(); 
        } catch (Throwable t) {
            t.printStackTrace();
        }
    }

輸出

診斷代碼列表：[Z590，E0800]

復(fù)雜物理層運(yùn)行狀況標(biāo)志：空

預(yù)期輸出

診斷代碼列表：[Z590，E0800]

復(fù)雜物理層運(yùn)行狀況標(biāo)志：TRUE

推薦答案

您的規(guī)則將不符合‘F’、‘F7’、‘F9’…

考慮其他幾種方法：

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject($listOfString : listOfString)
            value: String(value in ("F77", "EOO", "F99") ) from $listOfString
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
end

根據(jù)documentation，需要

當(dāng)您可以將所有事實(shí)插入到Drools引擎的工作內(nèi)存中或在約束表達(dá)式中使用嵌套對(duì)象引用時(shí)，請(qǐng)避免使用from元素。

以下將導(dǎo)致規(guī)則針對(duì)每個(gè)EligibilityDomainObject僅觸發(fā)一次，而不是針對(duì)每個(gè)匹配值：

import static org.apache.commons.collections4.CollectionUtils.containsAny;

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject(containsAny(listOfString, "F77", "EOO", "F99"))
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
end

一次收集匹配值

import static org.apache.commons.collections4.CollectionUtils.intersection;
import static com.google.common.collect.Sets.newHashSet;

rule "Problems related to social environment"
    when
        $eligibilityDomainObject:EligibilityDomainObject(
            $values : intersection(listOfString, newHashSet("F77", "EOO", "F99")), 
            !$values.isEmpty())
    then
        $eligibilityDomainObject.setIsComplexPhysicalHealth(true);
        System.out.println($values);
end

這篇關(guān)于如何遍歷列表以檢查某項(xiàng)是否為另一個(gè)列表的成員的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，